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Easiest way to get the Electronic Configuration

Posted by Rohan Baidya on November 6, 2009 at 8:54 AM

We've learned the Afbau's principle but, for some who don't get it, this one may just come to be relevant.

 

Common for all, these are the capacity of every sub-shell:
{(no. of electron) on (sub-shell) [Acronym stood - as found on a search]}

  • 2 on s (spindle / sharp / spherical),
  • 6 on p (principal / peripheral),
  • 10 on d (dumbell / diffuse),
  • 14 on f (fundamental)

Now, first get this in: (the format of subshell)
 
s
s  p
s  p
s  d  p
s  d  p
s  f   d  p
s  f   d  p

then hit in the shell no. that makes

1s
2s  2p
3s  3p
4s  3d  4p
5s  4d   5p
6s  4f    5d  6p
7s  5f    6d  7p

Note:
s's shell no is from 1 - 7
p's shell no is from 2 - 7
d's shell no is from 3 - 6
f's shell no is from 4 - 5
To find the the electronic configuration of any element, you just have to remember the atomic number

For an anology:
to find the electronic configuration of
Tellurium
it's atomic no. is 52
fill in the format of the power of the sub shell so that their sum be 52.




The following made the total electron no. as 52
proof:
total number of electron in s sub shell : 2 X 5 = 10
total number of electron in d sub shell : 10 X 2 = 20
total number of electron in p sub shell : (6 X 3) + 4 = 22

(adding) : total electron in s sub shell + total electron in d sub shell + total electron in p sub shell
= 10 + 20 + 22
= 52

therefore, is the electronic configuration of Tellurium


Last Note for Disclaimers:
People do not use this in case of d-block elements or f-block because they are under influence of the d sub-shell.

  • In f-block, d always wants either to be d to the power 0 or 1
  • In d-block, d always wants either to be d to the power 10 when the electron number that was supposed to fill it in reaches near to 10 (i.e. 8 or 9)

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1 Comment

Reply Neha Shrestha
9:55 AM on November 6, 2009 
good job it's really amazing ....u r really smart guy n totally different 4rm others keep it up man.... i really appreciate...

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